Let v(t) be the 宇宙的膨胀速度 at time t. We now only



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送交者: lala 于 October 04, 2011 17:05:50:

回答: "too simple,sometimes naive":)) 由 玩笑 于 October 04, 2011 15:00:11:

can conclude that

v(t) is increasing (2011 年的炸药奖) and v(t)/t => 0 as t => infinity
(不能得炸药奖因为"too simple,sometimes naive":)).

Is it possible that

v(t) = a log t for some constant a > 0

or

v(t) = a t^{b} for some constants a > 0 and 0 < b < 1?



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