You should have a calculus book. I don't have one.



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送交者: lala 于 June 01, 2003 14:51:51:

回答: lala同学:看在宋美龄的份上,再拉兄弟一把 由 淇淇 于 June 01, 2003 04:53:16:

From z^3-k2=k3*t we get

dt = (3/k_3)(z^2) dz

Let w = y^{3}. Then y = w^{1/3} and

dw = ((3k_1)/(k_3))(w^{1/3})z)dz - ((3k_1)/(k_3)) z^{2} dz
= C (w^{1/3})z)dz - C z^{2} dz

where C = 3k_1)/(k_3). From

dw = C w^{1/3})z)dz (*)

we get

w = ( (C/2) z^{2} + C_{0} )^{3/2}

For how to find the solution for the equation

dw = C (w^{1/3})z)dz - C z^{2} dz (**)

you should go to some book to see if there is any formula
related to (*) and (**).




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